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The American Mathematics Competitions (AMC) are the first of a series of competitions in secondary school mathematics that determine the United States team for the International Mathematical Olympiad (IMO). The selection process takes place over the course of roughly four stages. At the last stage, the Mathematical Olympiad Summer Program (MOP), the United States coaches select six members to form the IMO team. The United States Math Team of 1994 is the only team ever to achieve a perfect score (all six members earned perfect marks), and is colloquially known as the 'dream team'.[1]

Art of Problem Solving's Richard Rusczyk solves the 2019 AMC 10 A #24. Problem solving—at least the phrase—has always been part of school math. Every math textbook series claims to emphasize it and every list of standards gives it special attention. Here in Oregon, the Department of Education's performance assessment in mathematics is a 'problem-solving' test. The AMC 10 tests mathematical problem solving with arithmetic, algebra, counting, geometry, number theory, and probability and other secondary school math topics. Problems are designed to be solved by students without any background in calculus or trigonometry. Resources Links. AMC homepage, their AMC 10 page, and practice problems. Individual problem and its solution AMC 10 - Art of Problem Solving The AMC 10 is a 25 question, 75 minute multiple choice Amc 10 Problem And Solutions The AMC 10 is a 25 question, 75 minute multiple choice examination in secondary school mathematics containing problems which can be understood and solved with pre-calculus concepts.

There are three levels:

  • the AMC 8, for students under the age of 14.5 and in grades 8 and below[2]
  • the AMC 10, for students under the age of 17.5 and in grades 10 and below
  • the AMC 12, for students under the age of 19.5 and in grades 12 and below [3]

Students who perform well on the AMC 10 or AMC 12 competitions are invited to participate in the American Invitational Mathematics Examination (AIME). Students who perform well on the AIME are then invited to the United States of America Mathematical Olympiad (USAMO) or United States of America Junior Mathematical Olympiad (USAJMO). Students who do exceptionally well on the USAMO (typically around 30 students) are invited to go to the Mathematical Olympiad Summer Program (MOSP or more commonly, MOP), and six students are selected from the top twelve scorers on the USAMO (through yet another competition, the Team Selection Test (TST)) to form the United States International Math Olympiad Team.

American Mathematics Competitions is also the name of the organization, based in Washington, DC, responsible for creating, distributing and coordinating the American Mathematics Competitions contests, which include the American Mathematics Contest, AIME, and USAMO. The American Mathematics Competitions organization also conducts outreach to identify talent and strengthen problem-solving in middle and high school students. [4]


History[edit]

The 'members of the Committee on the American Mathematics Competitions (CAMC) are dedicated to the goal of strengthening the mathematical capabilities of our nation's youth. The CAMC believes that one way to meet this goal is to identify, recognize and reward excellence in mathematics through a series of national contests called the American Mathematics Competitions'. The AMC include: the American Mathematics Contest 8 (AMC 8) (formerly the American Junior High School Mathematics Examination) for students in grades 8 and below, begun in 1985; the American Mathematics Contest 10 (AMC 10), for students in grades 9 and 10, begun in 2000; the American Mathematics Contest 12 (AMC 12) (formerly the American High School Mathematics Examination) for students in grades 11 and 12, begun in 1950; the American Invitational Mathematics Examination (AIME), begun in 1983; and the USA Mathematical Olympiad (USAMO), begun in 1972.[5]

YearsNameNo. of questionsComments
1950–1951Annual High School Contest50New York state only
1952–1959Nationwide
1960–196740
1968–197235
1973Annual High School Mathematics Examination35
1974–198230
1983–1999American High School Mathematics Examination30AIME introduced in 1983, now is a middle step between AHSME and USAMO

AJHSME, now AMC 8, introduced in 1985

2000–presentAmerican Mathematics Competition25AHSME split into AMC10 and AMC12
A&B versions introduced in 2002.

USAMO split into USAJMO and USAMO in 2010. AMC 10 qualifiers who pass AIME go to USAJMO, instead of USAMO. USAJMO is supposed to be easier than USAMO.

Benefits of participating[edit]

There are certain rewards for doing well on the AMC tests. For the AMC 8, a perfect score may earn a book prize or a plaque (as it did for the students who achieved perfect scores in 2002); a list of high scoring students is also available to colleges, institutions, and programs who want to attract students strong in mathematics. This may earn a high scorer an invitation to apply to places like MathPath, a summer program for middle schoolers. The top-scoring student in each school is also awarded a special pin.

For the AMC 10 and AMC 12, a high score earns recognition (in particular, perfect scorers' names and pictures are published in a special awards book); as with the AMC 8, a list of high-scoring students is also available to colleges, institutions, etc. The top-scoring student in each school is awarded a special pin, or a bronze, silver, or gold medal, depending on how many times he or she was the top scorer.

In addition, high scorers on the AMC 10 and AMC 12 qualify to take the next round of competitions, the 3-hour long American Invitational Mathematics Examination (AIME), typically held in March or April. Any student who scores in the top 2.5% on the AMC 10 or scores in the top 5% on the AMC 12 is invited to take the AIME.

The combined scores of the AMC 12 and the AIME are used to determine approximately 270 individuals that will be invited back to take a 9-hour, 2-day, 6-problem session of proofs known as the United States of America Mathematical Olympiad (USAMO), while the combined scores of the AMC 10 and the AIME are used to determine approximately 230 individuals that will be invited to take the United States of America Junior Mathematical Olympiad (USAJMO), which follows the same format. Approximately thirty students are selected based on their USAMO performance to be trained at the Mathematical Olympiad Summer Program, or MOSP (better known as MOP to its participants). Approximately 12 of the top USAJMO scorers are invited as well. Unless qualifying for a particularly high level, all students must be in 9th grade or higher to be admitted into MOSP, and high school seniors are admitted only if they are members of that year's IMO team.

Math Problem Solvingamc10

During this summer camp, a 3-day competition (the TSTST) is held to determine the approximately 18 individuals who will form the TSTST group. These individuals take a series of contests throughout the year, such as the Asian Pacific Mathematics Olympiad, to finally pick the 6 member US Mathematics Team that will represent the US at the International Math Olympiad. The current head coach of the US IMO team is Po-Shen Loh from Carnegie Mellon University.[6]

Rules and scoring[edit]

AMC 8[edit]

The AMC 8 is a 25 multiple-choice question, 40-minute competition for middle schoolers designed to promote the development and enhancement of problem-solving skills.[5] No problems require the use of a calculator, and their use has been banned since 2008. Though the competition is typically held on a Thursday in November, in 2018 the AMC 8 took place on Tuesday, November 13.

The AMC 8 is scored based on the number of questions answered correctly only. There is no penalty for getting a question wrong, and each question has equal value. Thus, a student who answers 23 questions correctly and 2 questions incorrectly receives a score of 23. This is not a mandatory test; i.e. no school has to take it, but some schools choose to, mainly to encourage growth in mathematics among their students.

Rankings and awards[edit]

Ranking[7]

Based on questions correct:

  • Distinguished Honor Roll: Top 1% (has ranged from 19-25)
  • Honor Roll: Top 5% (has ranged from 15-19)

Awards

  • A Certificate of Distinction is given to all students who receive a perfect score.
  • An AMC 8 Winner Pin is given to the student(s) in each school with the highest score.
  • The top three students for each school section will receive respectively a gold, silver, or bronze Certificate for Outstanding Achievement.
  • An AMC 8 Honor Roll Certificate is given to all high scoring students.
  • An AMC 8 Merit Certificate is given to high scoring students who are in 6th grade or below.

AMC 10 and AMC 12[edit]

The AMC 10 and AMC 12 are 25 question, 75-minute multiple choice competitions in secondary school mathematics containing problems which can be understood and solved with pre-calculus concepts. As of 2020, the use of calculators is permitted on both the AMC 10 and AMC 12.[8][9]

High scores on the AMC 10 or 12 can qualify the participant for the American Invitational Mathematics Examination (AIME).[10] On the AMC 10, the top 2.5% make it; around 105 to 115 points. On the AMC 12, the top 5% make it; around 85 to 95 points.

The competitions are scored based on the number of questions answered correctly and the number of questions left blank. A student receives 6 points for each question answered correctly, 1.5 points for each question left blank, and 0 points for incorrect answers. Thus, a student who answers 24 correctly, leaves 1 blank, and misses 0 gets 24×6+1.5×1=145.5{displaystyle 24times 6+1.5times 1=145.5} points. The maximum possible score is 25×6=150{displaystyle 25times 6=150} points; in 2006, the AMC 12 had a total of 17 perfect scores between its two administrations, while the AMC 10 had 89.

From 1974 until 1999, the competition had 30 questions and was 90 minutes long, scoring 5 points for correct answers. Originally during this time, 1 point was awarded for leaving an answer blank, however, it was changed in the late 1980s to 2 points. When the competition was shortened as part of the 2000 rebranding, the value of a correct answer was increased to 6 points and the number of questions reduced to 25 (keeping 150 as a perfect score). In 2001, the score of a blank was increased to 2.5 to penalize guessing. The 2007 competitions were the first with only 1.5 points awarded for a blank, to discourage students from leaving a large number of questions blank in order to assure qualification for the AIME. For example, prior to this change, on the AMC 12, a student could advance with only 11 correct answers, presuming the remaining questions were left blank. After the change, a student must answer 14 questions correctly to reach 100 points.

The competitions somewhat overlap, with the medium-hard AMC 10 questions being the same as the medium-easy ones on the AMC 12. Since 2002, two administrations have been scheduled, so as to avoid conflicts with school breaks. Students are eligible to compete in an A competition and a B competition, and may even take the AMC 10-A and the AMC 12-B, though they may not take both the AMC 10 and AMC 12 from the same date.[3] If a student participates in both competitions, they may use either score towards qualification to the AIME or USAMO/USAJMO.

See also[edit]

  • American Invitational Mathematics Examination (AIME)
  • United States of America Mathematical Olympiad (USAMO)
  • Mathematical Olympiad Summer Program (MOSP or MOP)
  • International Mathematical Olympiad (IMO)

References[edit]

  1. ^'United States of America'. International Mathematical Olympiad. Retrieved 28 December 2020.
  2. ^'AMC 8'. Mathematical Association of America. Retrieved 29 December 2020.
  3. ^ ab'AMC 10/12'. Mathematical Association of America. Retrieved 28 December 2020.
  4. ^About AMC | MAA AMC. Maa-amc.org. Retrieved on 2020-06-24.
  5. ^ abAmerican Mathematics Competitions | Mathematical Association of America. Amc-reg.maa.org. Retrieved on 2013-08-14.
  6. ^'United States of America'. International Mathematical Olympiad. Retrieved 28 December 2020.
  7. ^'American Mathematics Contest 8'. Mathematical Association of America. Retrieved 28 December 2020.
  8. ^'AMC 10 Info Page'. Mathematical Association of America. Retrieved 28 December 2020.
  9. ^'AMC 12 Info Page'. Mathematical Association of America. Retrieved 28 December 2020.
  10. ^American Mathematics Competitions | Mathematical Association of America. Amc.maa.org. Retrieved on 2013-08-14.

External links[edit]

Retrieved from 'https://en.wikipedia.org/w/index.php?title=American_Mathematics_Competitions&oldid=997011454'

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Example:
The figure shows a series of rectangles where each rectangle is bounded by 10 dots.
a) How many dots are required for 7 rectangles?
b) If the figure has 73 dots, how many rectangles would there be?


Solution:

Rectangles PatternTotal dots
11010
210 + 717
310 + 1424
410 + 2131
510 + 2838
610 + 3545
710 + 4252
810 + 4959
910 + 5666
1010 + 6373

a) The number of dots required for 7 rectangles is 52.

b) If the figure has 73 dots, there would be 10 rectangles.

Example:
Each triangle in the figure below has 3 dots. Study the pattern and find the number of dots for 7 layers of triangles.


Solution:

LayersPatternTotal dots
133
23 + 36
33 + 3 + 410
43 + 3 + 4 + 515
53 + 3 + 4 + 5 + 621
63 + 3 + 4 + 5 + 6 + 728
73 + 3 + 4 + 5 + 6 + 7 + 836

The number of dots for 7 layers of triangles is 36.


Example:
The table below shows numbers placed into groups I, II, III, IV, V and VI. In which groups would the following numbers belong?
a) 25
b) 46
c) 269

I 1 7 13 19 25
II 2 8 14 20 26
III 3 9 15 21 27
IV 4 10 16 22
V 5 11 17 23
VI 6 12 18 24
Math Problem Solvingamc10

Solution:
The pattern is: The remainder when the number is divided by 6 determines the group.
a) 25 ÷ 6 = 4 remainder 1 (Group I)
b) 46 ÷ 6 = 7 remainder 4 (Group IV)
c) 269 ÷ 6 = 44 remainder 5 (Group V)

Example:
The following figures were formed using matchsticks.


a) Based on the above series of figures, complete the table below.

Number of squares 1 2 3 4 5 6 7 8
Number of triangles 4 6 8 10
Number of matchsticks12192633

b) How many triangles are there if the figure in the series has 9 squares?

c) How many matchsticks would be used in the figure in the series with 11 squares?

Solution:
a)

Number of squares 1 2 3 4 5 6 7 8
Number of triangles 4 6 8 10 12 14 16 18
Number of matchsticks12192633 40 47 54 61

b) The pattern is +2 for each additional square.
18 + 2 = 20
If the figure in the series has 9 squares, there would be 20 triangles.

c) The pattern is + 7 for each additional square
61 + (3 x 7) = 82
If the figure in the series has 11 squares, there would be 82 matchsticks.



Example:
Seven ex-schoolmates had a gathering. Each one of them shook hands with all others once. How many handshakes were there?

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Solution:

Cached

A B C D E F G
A
B
C
D
E
F
G
HS 654321

Total = 6 + 5 + 4 + 3 + 2 + 1 = 21 handshakes.

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